A certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?
(A) 7
(B) 6
(C) 5
(D) 4
(E) 3
Answer is C
i.e. 5 more matches team can lose
Ans is 7
2/3 game played=> so total no of game 30.
3/4 to win => 22.5 min to win ~23
so 7 to lose
Yup, 7 to lose…They have already lost 3…so they can just afford 4 more.
Ans: D
ya, Deeks
u r right
4 more they can afford.
Ans:D
Let the total games to be played be X
The total games played till date is 17 + 3 = 20
2X/3 = 20
X = 30
Pending Games are then 30-20 = 10
For winning a minimum of 3/4 of the total games, the team can lose a maximum of X/4 games : thus it can lose 30/4 = a max of 7.5 == 7 games
thus its allowed to lose 4 more games
Ans is D
Ans is D
its D
D
guys u have not read the q carefully it is mentioned that “What is the greatest number of the remaining games that the team can lose ” it asks from the remaining number of games the answer is 4 not 7 and its d option
D – z da ans