Solution Y is 30 percent liquid X and 70 percent water. If 2 kilograms of water evaporate from 8 kilograms of solution Y and 2 kilograms of solution Y are added to the remaining 6 kilograms of liquid, what percent of this new solution is liquid X?
A) 30%
B) 100/3 %
C) 75/2 %
D) 40%
E) 50%
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C…..Out of 8Kg mixture we have 5.6Kg water and 2.4Kg X. From this 2 Kg water evaporates and we are left with 3.6Kg water.
Now 2Kg of solution has 1.4Kg water and .6Kg X. Hence the total mixture is 8 Kg with 3Kg X and 5Kg water. Hence X is 3*100/8 = (75/2)%
c : If we consider , sol X and Water in weight ratios . Can this problem be solved , if X / Water are in volume terms .
(3/8) * 100% = 75/2 % Option C
yes it is C
well convinced with Nitin’s Explanation
c)
an easier method would be to consider the 2 lit to be added before evaporation
then we have 10 kg(3kg liq X+7 kg water)
on evaporation we have 8 kg (3kg liq X+5 kg water)
thus ans is (3/8)*100=75/2