statement 1 is not sufficient ( consider the cases 1/4 ^ 1/2 > 1/6 but 1/4 1 as well as 5>1 )
statement 2 is not sufficient ( ( -1/2 ) ^ 3 = -1/8 > -1/6 yet -1/2 -126 -> -5>-126 )
Statements 1&2 fixes the odd cases and thus the answer is C
Ans C.
From one.
assume, x = 0.16 and y = 0.3 . Here, x y.
x = 4 and y = 1. Here, x > y, and also x^ 0.5 = 2 > y.
So (1) is not enough to answer.
From 2.
Assume,
x = 4 and y = 1. Here x > y and also x ^ 3 = 64 > y.
x = 2 and y = 3. Here x y.
So (2) alone not enough to answer.
E
option c
Statement 1 alone is necessary and sufficient, but Statement 2 alone is not
statement 1 is not sufficient ( consider the cases 1/4 ^ 1/2 > 1/6 but 1/4 1 as well as 5>1 )
statement 2 is not sufficient ( ( -1/2 ) ^ 3 = -1/8 > -1/6 yet -1/2 -126 -> -5>-126 )
Statements 1&2 fixes the odd cases and thus the answer is C
Is x > y?
(1) x^0.5 >y = this can be written as root of x. x=0.0036 and y=0.0025 OR x=0.025 & y=0.1…cannot determine
(2) x^3>y = this helps to say x is an integer
therefore, using both yes x>y.
A
C
FRM 1st
Ans C.
From one.
assume, x = 0.16 and y = 0.3 . Here, x y.
x = 4 and y = 1. Here, x > y, and also x^ 0.5 = 2 > y.
So (1) is not enough to answer.
From 2.
Assume,
x = 4 and y = 1. Here x > y and also x ^ 3 = 64 > y.
x = 2 and y = 3. Here x y.
So (2) alone not enough to answer.
But both together,
x = 0.16 and y = 0.3. Here x
i have one doubt
if x is negative, what will be x^0.5 ?
whether positive or negative??
for the first one i think the answer is
Statement 1 is sufficient to ansewr the question but not 2
Second question , i dont think i quiet understand this question..
|x||x| = 3x-2 is this what they mean?