Comments on: DS Question

By: aryan

aryan — Tue, 23 Mar 2010 15:50:47 +0000

By: dp

dp — Thu, 11 Mar 2010 16:42:49 +0000

option c

By: Kofi DL

Kofi DL — Wed, 10 Mar 2010 16:37:00 +0000

Statement 1 alone is necessary and sufficient, but Statement 2 alone is not

By: Davidov

Davidov — Tue, 09 Mar 2010 20:51:07 +0000

statement 1 is not sufficient ( consider the cases 1/4 ^ 1/2 > 1/6 but 1/4 1 as well as 5>1 )
statement 2 is not sufficient ( ( -1/2 ) ^ 3 = -1/8 > -1/6 yet -1/2 -126 -> -5>-126 )
Statements 1&2 fixes the odd cases and thus the answer is C

By: amma4u

amma4u — Tue, 09 Mar 2010 18:18:58 +0000

Is x > y?

(1) x^0.5 >y = this can be written as root of x. x=0.0036 and y=0.0025 OR x=0.025 & y=0.1…cannot determine

(2) x^3>y = this helps to say x is an integer

therefore, using both yes x>y.

By: shilpa

shilpa — Thu, 07 Aug 2008 18:09:15 +0000

By: SD

SD — Thu, 24 Apr 2008 06:50:07 +0000

By: kv

kv — Mon, 07 Apr 2008 12:47:52 +0000

FRM 1st

By: sumanth toom

sumanth toom — Mon, 31 Mar 2008 06:16:30 +0000

Ans C.
From one.
assume, x = 0.16 and y = 0.3 . Here, x y.
x = 4 and y = 1. Here, x > y, and also x^ 0.5 = 2 > y.
So (1) is not enough to answer.
From 2.
Assume,
x = 4 and y = 1. Here x > y and also x ^ 3 = 64 > y.
x = 2 and y = 3. Here x y.
So (2) alone not enough to answer.

But both together,
x = 0.16 and y = 0.3. Here x

By: Venkat

Venkat — Sat, 29 Mar 2008 11:08:29 +0000

i have one doubt
if x is negative, what will be x^0.5 ?
whether positive or negative??