A forty gallons of gas is required to travel 400 miles using a 1200 CC engine. If the capacity of the engine is directly varying with the volume of gas, then how many gallons of gas required to travel 600 miles using 1500 CC engine ?
A) 20
B) 27.5
C) 37.5
D) 42.5
E) 75
Now Vote for best choice here
[polldaddy poll=2912223]
E). 42.5
Hi shaishav,
Can you explain it little bit ?
42.5
Can some explain this please.
I’m geeting an answer that’s not in the options. So it’s wrong for sure.
But here is what I did
40 g -> 400 M -> 1200 CC
x g -> 600 M -> 1500 CC
If 40 g -> 400 M -> 1200 CC
then 1g -> 10 M -> 1200 CC
If 1g -> 10 M -> 1200 CC
then 60 g -> 600 M –> 1200 CC
If 60 g -> 600 M –> 1200 CC
then x g -> 600 M -> 1500 CC
hence x= 75 gallons which is wrong…
Can anybody pl explain how the ans is derived . It is Ratio and Proportion Q
Take GMAT can you pl post the explaination .
Answer for This question is 75.
i think the possible solution is 75. Because IF the capacity of engine is directly proportional to volume of gas consumed then, more the capacity, more the gas needed. Also more the gas, more the distance covered. Then the equation would look like :
40 : x :: 400 : 600
1200 : 1500
=> x = (40X600X1500)/ (400×1200)
= 75 gallons
( Actually Posted by Sharon)
e
Actuallu I disagree…..with the solutio posted.
The question says the relationship exists between the volume of gas and the capacity of the engine, however while setting up the ratio euqation you have taken volume to miles. The soltuion acc to me should be:
40 gallon directly proportional to 1200 cc
40 gallons = k*1200 cc
xgallons = k*1600 cc ( since proportionality constant stays same)
therefore, 40/x = 1200/1600
x=50 gallons.
Answer is still E…we could have also used POE all the others were too small. Only contender was 42.5.
Your comments!
Answer is 75…. Even to travel the same distance of 400 miles… 50 gallons are required …. so travel more… u need an answer greater than 50… which gives the answer as E
Ans . E
THE QUESTION SAYS THAT THE CAPACITY OF THE ENGINE IS DIRECTLY PROPORTIONAL TO THE VOLUME OF THE GAS. CAPACITY OF THE ENGINE WOULD BE MEASURED BY THE MILEAGE THE VEHICLE GIVES. ACCORDINGLY IN THE FIRST CASE IT IS 10MILES/GALLON OF FUEL. SO FROM THE EQUATION (1200/10)=(1500/X), WHERE X WOULD BE THE NEW MILEAGE. SOLVINF FROM THIS AND XINDING THE VALUE OF X WE COME TO VOLUME OF FUEL NEEDED=48 GALLONS.
SO ANSWER OUGHT TO BE (E).
OPEN TO POINTING OUT FOR POSSIBLE FLAWS IN MY SOLUTION!!
40gallons ->400miles @1200cc
xg->400miles@1500cc =>x=50gallons
now 50gallons ->400miles
ygallons->600miles=> y= 75 gallons
ans. E
Answer is “E”
gas required and miles are directly related.
gas and engine capacity are directly related
—
Gas = k[miles*capacity]
Solve for k:
40 = k[400*1200]
k = 1/12000
——–
Equation:
Gas =(1/12000)[miles*capacity]
Gas = (1/12000)[600*1500]
Gas = 75 gallons
SO,answer is E.
Official Answer is …. We rectified the mistake & posted the official answer below.
Time is the most precious resource:
40*600/400*1500/1200.
the capacity is directly varying with 1200/1500
I also got 75.how come the answer is 42.5??can u plz xpln
@Aliva,
Now we added new poll as well so that we can gauge better response.
TGT
40* (1500/1200)* (600/400) = 75
E is the Correct answer
E…
75… waiting for explanation of 42.5 ..
It is question of continuous ratio,
a:b::c:d::e:f
a=40 c=400 e=1200
b=P d=600 f=1500
That goes like this adf=bce
40x600x1500=Px400x1200
So P=75
So correct answer is 75