AMOUNT OF BACTERIA PRESENT
Time Amount
1:00 P.M. 10.0 grams
4:00 P.M. x grams
7:00 P.M. 14.4 grams
Data for a certain biology experiment are given above. If the amount of bacteria present increased by the same fraction during each of the two 3-hour periods shown, how many grams of bacteria were present at 4:00 P.M.?
A. 12.0
B. 12.1
C. 12.2
D. 12.3
E. 12.4
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My Answer is 12.
Ans: 12
Even my answer is 12. Need your suggestions whether my approach to solve the question is right. I did:
(x-10)/10 = (14.4-x)/x
-> x^2-144=0
-> (x+12)(x-12)=0
Any other approaches or a much faster approach?
a
C
I will go with option C
y = fraction, x = 4:00pm amount
10+10y = x
y = 1/10 * (x-10)
x + xy = 14.4
x +x[1/10 * (x-10)] = 14.4
solve for x and get 12