Vertices of a quadrilateral ABCD are A(1,1), B(5,6), C(10,10) and D(6,5). What is the shape of the quadrilateral?
A. Square
B. Rectangle but not a square
C. Rhombus
D. Parallelogram but not a rhombus
E. None of these

Vertices of a quadrilateral ABCD are A(1,1), B(5,6), C(10,10) and D(6,5). What is the shape of the quadrilateral?
A. Square
B. Rectangle but not a square
C. Rhombus
D. Parallelogram but not a rhombus
E. None of these

Ans should be C.
Opposite arms are parallel and all the arms are equal. So it is a rhombus and parallelogram.
Arms are parallel because,
(10-6)/(10-5)=(5-1)/(6-1) and (6-1)/(5-1)=(10-5)/(10-6)
And Size is equal to (41)**(1/2).
D. Parallelogram but not a rhombus
Slope of opposite sides is the same but all four side are not equally long.
ans is C
as the slope of the opposite side are equal (opposite parallel sides)
so its a rhombus
Admin,
Wot’s the answer?
Its rhombus. because all sides are equal. Answer is C.
no doubt it’s c
(4 + 5)^0.5 = (5 + 4)^0.5 = (4 + 5 )^0.5 i.e side’s length is 3 and opp sides have same slope
theoritically speaking , after calculating till here…we have two options to select from …..1) square or 2) rhombus
now when we see that the product of slopes of adjacent sides is not
-1 we can conclude it is a rhombus
practically speaking…if you just plot the points roughly …there is no need to find the product of slopes
C
Answer is “C” it would be rhombus, as the length of opposite sides are equal & oppsite angles would be complimentary.
C
Ans : C
C
Ans: C as all the sides are equal and the slope of the opposite sides are equal.
the answer is C.it is Rhombus
answer is C. The figure should be a parallelogram (given the lines are parallel) and since all the sides are equal (in length), it is special case of parallelogram which is RHOMBUS.
the answer is d.because all side are equall and opposite side are parallel. Lenth of each side are square root(41).
a-b= -b(5,6)
– – 4
– -
a(11) —————–(1,6)
5
The Answer is option D .
Its ||gm and not rombus…
We have a tric to solve these types of questions…. If (x1,y1 ), (x2,y2 ) ,(x3,y3 ) ,(x4,y4 ) are 4 co-ordinates of a given quad. Then if x1+x3=x2+x4 and y1+y3=y2+y4 , then the quad is ||gm…
Ans: C
All sides are equal, so Rhombus.
Yes C
answer is C
answer is D
who said all sides are equal.
C
it will be d
C
C…
c
Polish ur concepts of CG…and u will find the answer is D…three cheers to those who got it right…for those who cudnt…stop posting answers unless u hv clear concepts abt figures
C.
ans is C..
please tell how the ans is D.? Which geometrical concept makes the ans D.
Answer is C
It is not a rectangle or a square because diagnols are not of equal length but product of the slopes of diagnols is -1 i.e. diagnols bisect each other at 90 degree, that makes it a rhombus
I think the answer is C.
Its not a Rhombus / Square ( 4 sides are not equal )
Not a Rectangle because its not right angled.
Only option D bcos its close to a IIgm
C
Official Answer: C.
answer is C
c
If a point(x,y) is equidistant from the two points (3,6)and(-3,4),then find the relation between x and y?
show that the triangle formed by the three points (5,-2), (6,4), (7,-2) is isoceles?
Lets us determine the value of segments AB, BC, CD and DA using the formula of distance between 2 coordinated points namely sqroot[(x1-x2)^2 + (y1-y2)^2]
Calculations yield to AB = BC = CD = DA = sqroot(41)
So answers B and D must discarded
To determine if it is a Square or a Rhombus, must determine the value of diagonal segments AC and BD
AC = sqroot(162)
BD = sqroot(2)
Since AC not = to BD it is a Rhombus !
So correct answer is C
its C
C