2 people are to be selected from 10 people, which include male and female. Is the probability that both them female greater than 1/2?
1) The number of females is greater than 5
2) The probability that both them are male is less than 1/10
A) Statement 1 alone is sufficient but statement 2 alone is not sufficient to answer the question asked.
B) Statement 2 alone is sufficient but statement 1 alone is not sufficient to answer the question asked.
C) Both statements 1 and 2 together are sufficient to answer the question but neither statement is sufficient alone.
D) Each statement alone is sufficient to answer the question.
E) Statements 1 and 2 are not sufficient to answer the question asked and additional data is needed to answer the statements.
D
I agree with D
My choice is E.
Mine is E.
I) W > 5 -> Assuming W=6 we have 6/10×5/9 = 1/3 (
It should be E, beacuse:
A) # of females > 5, that means it could be between 6 and 9
if we take 6 => prob = 6C2/10C2 = 1/3 which is prob = 9C2/10C2 = 4/5 which is > 1/2
hence A is not sufficient
B) With the prob of choosing both males as less than 1/10, it means that the number of men is either 2 or 3 as with 4, the prob of choosing 2 men will be more than 1/10.
If it is 2, that means # of females is 8 => prob of choosing 2 females is more than1/2
if it is 3, that means # of females is 7 => prob of choosing 2 females is less than 1/2
Hence B is insuffient
TOGETHER, they do not provide a specific number of females/males, so they together are insufficient.
Hence the answer should be “E”.
Correct answer E
E
E
E
E
E
if the number of females is either 8,9,10 then P(W)*P(W) will be greater than 0.5
( Because if the number of women are 7 then you get 0.49 )
1. Tells you W>5
2. Tells you number of men = 0,1,2 or 3
W = 7,8,9,10
Therefore you cannot say for sure since
P(7)*P(7) = 0.49
P(8)*P(8) = 0.64
My choice is E as the exact number of males and females cant found and also if assumptions are taken the probability p varies as
1>p>1/2
1/2>p>….
E is the right choice
D
Sorry the answer is E
e
i go with E
E
ans is E
E
B
The only way probability of choosing both men 1/2.
I believe Milind got close to it but his evaluation for B was a little inaccurate.
Gaurav
I think the answer is E.because with statement 1 we don’t get a definite answer.number of females can be 6,7,8 or 9.
and in statement 2 if probability that both r males is less than 1/10.then probability that both r not males would be 9/10.this includes 2 kinds of possibility 1 male 1 female or both females.so we cannot arrive to a particular solution.by combining also we cannot solve the problem as there r more than 1 answer.so my choice is E.
Ans is E.
Stmt is 1 nowhere sufficient.
Stmt 2 : the number of males should be 3 or 2 to make the probability less than 1/10.
Now if number of males = 3 then
P(MM) = 1/15, OK less than 1/10
P(FF) = 7/15, less than 1/2
Now if number of males = 2 then
P(MM) = 1/45, OK less than 1/10
P(FF) = 28/45, greater than 1/2
In both the case the value of p(FF) is not coming either greater or lesser to 1/2 and hence stmt is also not sufficient.
If we take both the stmt together, this will again not make any sense as stmt 1 came under the premise of above calculation.