What is the area of right triangle ABC below ?
1) AC^2=30
2) AB+BC=8
A) Statement 1 alone is sufficient but statement 2 alone is not sufficient to answer the question asked.
B) Statement 2 alone is sufficient but statement 1 alone is not sufficient to answer the question asked.
C) Both statements 1 and 2 together are sufficient to answer the question but neither statement is sufficient alone.
D) Each statement alone is sufficient to answer the question.
E) Statements 1 and 2 are not sufficient to answer the question asked and additional data is needed to answer the statements.
Cannot be determined Choice is E
C) Both statements 1 and 2 together are sufficient to answer the question but neither statement is sufficient alone.
AB = h ; BC = b ; AC = hypo
Area = 1/2 * b * h
1) AC^2=30 which means hypo^2 = 30.
2) AB+BC=8 which means h + b = 8.
Since ABC is a rt. angle tri.
h^2 + b^2 = hypo^2.
h^2 + b^2 = 30 and we have
h + b = 8. Therefore, h = 8 – b. Using substitution we can find h, b and hence area.
Righ pat, answer is C
we need to find ABXBC/2
AC^2 = AB^2+BC^2 = 30
Ab+BC = 8 when squared becomes AB^2+BC^2 +2XABXBC = 64
Subsituting the above equation this equation becomes
2XABXBC = 64-30= 34
So ABXBC/2 = 34/4
Welldone Pat… You are correct.
Ans: C
C
C
answer is C
C
Its C
c all the way
C, two equations, two unknowns. The only way it would be something else, is if AC^2 were a perfect square and fit one of those nice happy triangles everyone knows about (345, etc etc etc)
ans c) is right…
c
c
Cannot be determined because b has 2 values and thus h has 2 values resulting in two areas, i.e.; ambiguity, so E
Yes.. C is the correct answer.
c
Answer is C
The answer is C
given that
1) AC^2=30
2) AB+BC=8
(AB+BC)^2=64
=>30+2*AB*BC=64 (BCOZ AC^2=AB^2+BC^2)
=>0.5*AB*BC=(64-30)/4
So we can find the area using both the conditions. Hence ‘C’ is the answer
C As AB+BC is given and AC^2 is given
also (AB+BC)^2-2AB BC = AC^2
c
C
OPtion C
C
Solution:
1. Not Sufficient
2. Not Sufficient
1+2 : Suffcient
Area of ABC = (AB X AC)/2
(AB+BC)^2 = AB^2 + BC^2 + 2 AB X AC
64 = 30 + 2 AB X AC
AB X AC = 17
So the Area of ABC = (AB X AC)/2 = 17/2 SO answer is C