The number of different arrangements that can be made with the letters of the word ”GRATITUDE” in which the T’s are together?
A) 9!*2!
B) 8!
C) 9!
D) 81*2!
E) None of these
GMAT Question of the Day: Permutation and Combination
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B
B
8×7!
8!
Ans: B
B. 8!
Correct answer is B
B) 8!
Yes B
b
8 ways of choosing TT adjacent in 9 numbers
T T _ _ _ _ _ _ _
_ T T _ _ _ _ _ _
_ _ T T _ _ _ _ _
_ _ _ T T _ _ _ _
_ _ _ _ T T _ _ _
_ _ _ _ _ T T _ _
_ _ _ _ _ _ T T _
_ _ _ _ _ _ _ T T
the rest of the 7 numbers can be arranged in 7! ways.
Therefore total = 8*7! = 8!
Is there any easier & faster way of doing this
(G) (R) (A) (TT) (I) (U) (D) (E)
8 letters!
so B—>8!
answer is 8!
But can anybody give the answer of below question
A man went to ATM but he forgot the last 2 digits of password than what is probality that hw will succed with in the 3 trials ?
keyur: 3%?
number of possibilities for two digits = 100 (00-99)
keyur
success probabability 1/100 & failure probability 99/100 for each chance.
So for your condition he will fail in first two attempts & succeed in third.
Probability of total this event= (99/100)^2 X (1/100)
I am confused…wont it be 8! x 2! because there would be 8! ways to arrange letters G R A U I D E TT and
2! ways to arrange T T inter-se..
So the answer would be “E”..none of these..
Anyone supporting my view..???:)
keyur.
the answer is
( 1/100) + ( 99/100 * 1/100) + ( 99/100* 98/100 * 1/100)
option B
Ans. B
The answer should be 8!*2!.
(G) (R) (A) (TT) (I) (U) (D) (E) -> 8!
But the 2 T’s can be arranged in 2! ways again.
Sappan i support you!!
Undoubtedly Ans is B