At a certain business school, 400 students are members of the sailing club, the wine club, or both. If 200 students are members of the wine club and 50 students are members of both clubs, what is the probability that a student chosen at random is a member of the sailing club?
A. 1/2
B. 5/8
C. 1/4
D. 3/8
E. 3/5
Authors bio is coming up shortly. 
B. 250/400 = 5/8
Sorry, but it seems that the answer is A because, 200 students are members of the wine club and other remaining students are members of the sailing club or both. So the probability will be:
200/400 = 1/2
It should be B.
There are 200 members of wine club, x of sailing club and 50 common. That means that sailing club will have 200+x-50=400
=> x=250 members [ n(A) + n(B) – n(A intersection B) = n(AUB)
The probability should be 250/400 = 5/8
a
b
B
B
A.
“If 200 students are members of the wine club and 50 students are members of both clubs…”. I assume this to mean that there are 200 students of the wine club; of that 200, 50 are also in the sailing club. This means that there are 150 students in the wine club only; 50 students in both; and 200 students in the sailing club only.
I think others are reading this and thinking it means there are 200 students in the wine club only; however, it does not state that.
B
take gmat.. what’s your take?
take GMAT team..Is the question ambiguous??i think answer is A
i think the answer is 200/400=1/2 as it is not given that 200 members are the members of wine club only
B.
Well, the question asks what is the probability that the member chosen is from sailing club. It does not mention “what is the probability that the member chosen is from sailing club ONLY”. So as per the question, the member should be in the sailing club…does not matter if he also belongs to wine club.
hence … 250/400 = 5/8.
It has to 5/8.
Sailing Club: 200 + 50 (both) out of 400
Probability = 250/400 = 5/8
sailing club= total- win club + both= 250. probability 250/400 B is ans.
In continuation of the explanation given by ‘gmat_guy.
““If 200 students are members of the wine club and 50 students are members of both clubs…â€. I assume this to mean that there are 200 students of the wine club; of that 200, 50 are also in the sailing club. This means that there are 150 students in the wine club only; 50 students in both; and 200 students in the sailing club only.”
==>Only wine club students = 150, Total students = 400. So probability of finding only wine club student = P(w) = 150/400= 3/8.
So P’(W) is probability of finding a non-only-wine (which is a wine & sail or a sail student) = 1 – 3/8 = 5/8. the correct answer..
A better way of solving is to directly find out P(S) = 250/400 = 5/8.
B
please give the accurate and correct answer… multiple answers can confuse ppl… team plz…
A
A
B 5/8.
n(S Union W) = n(S) + n(W) – n(S Intersection W)
400 = n(S) + 200 – 50
=> n(S) = 250
Therefore, Reqd Probability = 250/400 = 5/8
It’s A.
Total: 400
Wine Only: 200
Wine and Sailing: 50
Sailing Only: 150
There are 200 members of the Sailing Club of whom some are also members of the Wine Club. 200/400 = 1/2 = Answer A.
B
250/400 = 5/8 B is the answer
oh God thnx….I got it right.
A
Thanks to Gmat Team for the OA
Official Answer is B.
If you observe you can see the sum of row & column is in last line. Here we getting sailing club as 250 so answer will be 250/400.
Option B
B…
B
Answer is B
‘A’ could be answer if the question ask for “what is the probability that a student chosen at random is a member of the sailing club or both?”
Am I right GMAT team?
Nope !,
Answer will be “B”
Saying “member of the sailing club or both” or “member of the sailing club” is basically same thing.
B
x-50+200-50+50=400
x=250
so, 250/400 or , 5/8, B!!!!
Answer is B