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	<title>Comments on: Problem solving</title>
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		<title>By: Tapas</title>
		<link>http://www.takegmat.com/index.php/problem-solving-4/#comment-67989</link>
		<dc:creator>Tapas</dc:creator>
		<pubDate>Mon, 31 Aug 2009 09:37:50 +0000</pubDate>
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		<description>10/3</description>
		<content:encoded><![CDATA[<p>10/3</p>
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		<title>By: Navya</title>
		<link>http://www.takegmat.com/index.php/problem-solving-4/#comment-61944</link>
		<dc:creator>Navya</dc:creator>
		<pubDate>Thu, 12 Jun 2008 08:40:03 +0000</pubDate>
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		<description>Ans is 10/3</description>
		<content:encoded><![CDATA[<p>Ans is 10/3</p>
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	<item>
		<title>By: tat</title>
		<link>http://www.takegmat.com/index.php/problem-solving-4/#comment-61820</link>
		<dc:creator>tat</dc:creator>
		<pubDate>Wed, 11 Jun 2008 03:54:27 +0000</pubDate>
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		<description>ans is 10/3</description>
		<content:encoded><![CDATA[<p>ans is 10/3</p>
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		<title>By: pavan</title>
		<link>http://www.takegmat.com/index.php/problem-solving-4/#comment-61819</link>
		<dc:creator>pavan</dc:creator>
		<pubDate>Wed, 11 Jun 2008 03:39:23 +0000</pubDate>
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		<description>3^6x = 8100

therefore, 3^3x * 3^3x = 90 * 90
from above we can say, 3^3x = 90 -------------------------------i

the reqd eqn, is (3^(x-1))^3 =&gt; 3^3x - 3^3 =&gt; 3^3x/ 27 ------- ii

from i &amp; ii, sub 3^3x, so 3^3x/ 27 = 90/27 =&gt; 

10/3 ......... answer E .......

I&#039;ve posted the question from previous GMAT test paper</description>
		<content:encoded><![CDATA[<p>3^6x = 8100</p>
<p>therefore, 3^3x * 3^3x = 90 * 90<br />
from above we can say, 3^3x = 90 &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;-i</p>
<p>the reqd eqn, is (3^(x-1))^3 =&gt; 3^3x &#8211; 3^3 =&gt; 3^3x/ 27 &#8212;&#8212;- ii</p>
<p>from i &amp; ii, sub 3^3x, so 3^3x/ 27 = 90/27 =&gt; </p>
<p>10/3 &#8230;&#8230;&#8230; answer E &#8230;&#8230;.</p>
<p>I&#8217;ve posted the question from previous GMAT test paper</p>
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	<item>
		<title>By: Richa</title>
		<link>http://www.takegmat.com/index.php/problem-solving-4/#comment-61806</link>
		<dc:creator>Richa</dc:creator>
		<pubDate>Wed, 11 Jun 2008 02:20:45 +0000</pubDate>
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		<description>10/3
3^6x=8100, we get the value of x=100/9
then we substitue the value of x in the other equation.
Incase there is any other way of solving this problem please share.</description>
		<content:encoded><![CDATA[<p>10/3<br />
3^6x=8100, we get the value of x=100/9<br />
then we substitue the value of x in the other equation.<br />
Incase there is any other way of solving this problem please share.</p>
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	<item>
		<title>By: kapil dhawan</title>
		<link>http://www.takegmat.com/index.php/problem-solving-4/#comment-61755</link>
		<dc:creator>kapil dhawan</dc:creator>
		<pubDate>Tue, 10 Jun 2008 16:35:28 +0000</pubDate>
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		<description>pleas give the explanation of this problem</description>
		<content:encoded><![CDATA[<p>pleas give the explanation of this problem</p>
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	<item>
		<title>By: Patel</title>
		<link>http://www.takegmat.com/index.php/problem-solving-4/#comment-61664</link>
		<dc:creator>Patel</dc:creator>
		<pubDate>Tue, 10 Jun 2008 05:20:27 +0000</pubDate>
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		<description>10/3</description>
		<content:encoded><![CDATA[<p>10/3</p>
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