Comments on: There are 5 cars to be displayed in 5 parking spaces with all the cars facing the same direction

By: Neotapas

Neotapas — Mon, 09 May 2011 05:37:31 +0000

By: Aliva

Aliva — Wed, 25 Aug 2010 18:33:13 +0000

Thanks Take Gmat team.

By: Take GMAT Team

Take GMAT Team — Wed, 25 Aug 2010 18:23:42 +0000

Official Answer is A.

By: Aliva

Aliva — Wed, 25 Aug 2010 18:15:35 +0000

5!/3!=(5*4*3!)/3!=20

By: Kofi DL

Kofi DL — Tue, 08 Dec 2009 10:02:18 +0000

20 ways!…

By: bsol

bsol — Sun, 06 Dec 2009 02:34:54 +0000

A
good review question

By: geewhiz

geewhiz — Fri, 27 Nov 2009 10:11:04 +0000

Keep it simple!! 3 red cars can be arranged in 5C3 ways i.e 10. The balance 2 cars can be arranged in 2 ways( since there are now only 2 places vacant to display the blue and yellow car). Therefore total no. of ways=10*2=20

By: Anita

Anita — Sat, 15 Dec 2007 16:16:42 +0000

Permutation=5x4x3x2x1
Combination- Permutation/3! three are alike=20

By: Senjaya Khoo

Senjaya Khoo — Sat, 08 Dec 2007 04:24:07 +0000

got it:
the formula was:
Combination! : n!
so
5! : 3!
5x4x3x2x1 : 3x2x1 = 5×4 = 20

By: Senjaya Khoo

Senjaya Khoo — Sat, 08 Dec 2007 04:21:08 +0000

A – 20
dummy style:
11123
11231
12311
23111
11132
11321
13211
32111
21311
12131
11213
31211
13121
11312
21131
12113
31121
13112
21113
31112
formula :
still cracking