The value of a diamond is proportional to the square of its weight.

The value of a diamond is proportional to the square of its weight. It is broken into three pieces whose weights are in the ratio 3:2:5.Find the loss incurred due to breakage if the value of the original diamond is USD 20,000.

A. 12,600

B. 12,200

C. 12,000

D.12,400

E. 13,300

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7 Comments Post a Comment
  1. @Rajib Banerjee

    Thanks a lot for good explanation. We did the modification as per your request.

    Team TakeGMAT.com

  2. Rajib Banerjee says:

    Please replace the “?” by “square root”. Sorry for the confusion.

  3. Rajib Banerjee says:

    Please replace the “?” by “?”

  4. Rohit says:

    Answer is D as expaned by Rajib

  5. Ritesh Mistry says:

    Ans D

  6. Rajib Banerjee says:

    Answer is D.
    Explanation : Let x be the original weight => x^2 = 20000 => x = 100^2. Since the pieces were broken in the ratio of 3:2:5, their respective weights is 30^2, 20^2 and 50^2. Their respective value is 1800$, 800$ and 5000$. (value of a diamond is proportional to the square of its weight) Their combined value is 7600$. The loss is therefore 20000 – 7600 = 12400$.

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