There were 36.000 hardback copies of a certain novel sold before the paperback version was issued. From the time the first paperback copy was sold until the last copy of the novel was sold. 9 times as many paperback copies as hardback copies were sold. If a total of 441.000 copies of the novel were sold in all, how many paperback copies were sold?
(A) 45.000
(B) 360.000
(C) 364.500
(D) 392.000
(E) 396.900
P = 9 (H-36)
Since 9 times as many paperback were sold “from the time the 1st paperback was sold. But when the 1st paperback was sold already 36 Hardcovers were sold.
H = P/9 + 36
——-
P+H=441
P+P/9+36=441
10/9 P = 405
P=405 * 10 / 9 = 364.5
So thats the correct answer = C
But how can the paper back be half ? ( Logically you cannot sell half a book?)
——————————————
441000-36000=405000
9 part of 405000 is 364.500.
C is the right choice.
C.
C
C
C is the correct choice
Ans for the above q is option C.
c
C
the answer is C
C
correct me if i am wrong isn ‘t it E ,I mean the question does not tell you that they have stop selling hardbacks right so by that logic 36,000 + x number of harbacks were sole hence 9(36,000 + x) paperbacks were sold .
Therefore total copies sold is 9(36,000 + x) + 36,000 + x = 10(36,000 + x) = 441000
solving this x = 8100
total paperbacks sold = 396.900
I think it is E as well.